Find k for real roots
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Find k for real roots
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WebJun 26, 2024 · Adding +k we are traslating graph up or down if k is positive or negative respectively and this fact we can eliminate 2 real roots adding 2 complex roots. (if a polinomial has a complex root, then his conjugate is also root). Hope this helps Answer link KillerBunny Jun 26, 2024 −2 ≤ k ≤ 2 Explanation: WebFind values of k such that : Example 1 : kx2 + 12x + 2 = 0 has a repeated root Solution : Given, kx2 + 12x + 2 = 0 By comparing ax2 + bx + c = 0 in the given equation, we get Here, a = k, b = 12, and c = 2 Since the roots are real and equal, then D = 0 b2 – 4ac = 0 (12)2 – 4 (k) (2) = 0 144 – 8k = 0 -8k = -144 k = 144/8 k = 18
WebFor getting real and distinct roots the discriminant of the quadratic equation should be greater than zero. Therefore, D>0 Now, Here a=k, b=2, c=1. Therefore, 4k<4 Hence, for … WebFrom the quadratic formula, x = -b/2a +/- (sqrt (bb-4ac))/2a If 1 root is non-real, then the discriminant is negative, and both roots have an imaginary component; in one root it's …
WebSolution Verified by Toppr Correct option is C) If 2x 3+3x+k=0 has 2 distinct real roots in [0,1], then f(x) will change sign once in the interval. But, f(x)=6x 2+3>0 for 0≤x≤1 So, no value of k exists for which there are two real roots of the equation in [0,1] Video Explanation Was this answer helpful? 0 0 Similar questions WebThe set of values of k for which the given quadratic equation has real roots. 2x2+kx+2=0 is k ≤ 9. Q. The set of values of k for which the given below quadratic equation has the real roots is k ≤4√6. 2x2+kx+3=0 . Q. Find the value of k, for which the quadratic equation 2x2+kx+3=0 has two real equal roots. Q.
WebIn mathematics and computing, a root-finding algorithm is an algorithm for finding zeros, also called "roots", of continuous functions. A zero of a function f , from the real numbers to real numbers or from the complex numbers to the complex numbers, is …
WebFor the above equation, the roots are given by the quadratic formula as x = − b ± b 2 – 4 a c 2 a Let us take a real number k > 0. Now, we know that √k is defined and is a positive quantity. Is √ {-k} a real number? The answer … ralf althoffWebA: Sol Q: Find the values of k for which the equation x3+5kx+16=0 has no real roots A: Given- x2+5kx+6=0 To Find- The value of k for the above quadratic equation has no real roots.… Q: B. Find the value of k that makes x2 + (k + 5)x + (5k + 1) a perfect square. A: Click to see the answer over 40 women with no makeups on igWebFind the value of k for which the given equation has real roots: kx 2 - 6x - 2 = 0 Advertisement Remove all ads Solution The given equation is : kx 2 - 6x - 2 = 0 Here, a = … ralf almerothWebSolution The given equation is : kx 2 - 6x - 2 = 0 Here, a = k, b = -6 & c = -2 This equation has real root if b 2 - 4ac ≥ 0 ⇒ (-6) 2 - 4 x k x (-2) ≥ 0 ⇒ 36 + 8k ≥ 0 ⇒ 8k ≥ -36 ⇒ k ≥ - 36 8 ⇒ k ≥ - 9 2. Concept: Nature of Roots of a Quadratic Equation Is there an error in this question or solution? Chapter 6: Quadratic Equation - Exercise 1 ralf alles biontechWebTake the Square Root. Example: 2x^2=18. Quadratic Formula. Example: 4x^2-2x-1=0. About quadratic equations Quadratic equations have an x^2 term, and can be rewritten to have the form: a x 2 + b x + c = 0. Need more problem types? Try MathPapa Algebra Calculator. Upgrade to Premium ralf alwaniWebMar 22, 2024 · Transcript. Ex 4.4 ,2 Find the values of k for each of the following quadratic equations, so that they have two equal roots. (ii) kx (x – 2) + 6 = 0 kx (x – 2) + 6 = 0 kx2 … ralf althoff mendritzkiWebQ: Find the values of k for which the equation x3+5kx+16=0 has no real roots A: Given- x2+5kx+6=0 To Find- The value of k for the above quadratic equation has no real roots.… Q: Assume the quadratic equation x squared +kx- 8 factors. over 4.5 goals prediction